The internal resistance of a cell of emf 2 V is 0.1 π. If it is connected to a resistance of 39 π, then the voltage across the cell will be (in volts)

Question

The internal resistance of a cell of emf 2 V is 0.1 π. If it is connected to a resistance of 39 π, then the voltage across the cell will be (in volts) (A) 2 V (B) 0.5 V (C) 1.95 V (D) 2.5 V

Tardigrade Admin · Accepted Answer

We know r=((E/V)-1) R hence, R=39 π, E=2.0 V, r=0.1 Ω hence, V=1.95 V

Q. The internal resistance of a cell of emf $2 V$ is $0.1 π$ . If it is connected to a resistance of $39 π$ , then the voltage across the cell will be (in volts)

2 V

0.5 V

1.95 V

2.5 V

We know $r = (\frac{E}{V} - 1) R$
hence, $R = 39 π,$
$E = 2.0 V$ ,
$r = 0.1 Ω$
hence, $V = 1.95 V$

Q. The internal resistance of a cell of emf 2V is 0.1π. If it is connected to a resistance of 39π, then the voltage across the cell will be (in volts)

2 V

0.5 V

1.95 V

2.5 V

We know r=(VE​−1)R hence, R=39π, E=2.0V, r=0.1Ω hence, V=1.95V

Q. The internal resistance of a cell of emf $2 V$ is $0.1 π$ . If it is connected to a resistance of $39 π$ , then the voltage across the cell will be (in volts)

We know $r = (\frac{E}{V} - 1) R$
hence, $R = 39 π,$
$E = 2.0 V$ ,
$r = 0.1 Ω$
hence, $V = 1.95 V$