The internal resistance of a cell of e.m.f. 2 V is 0.1 Ω It is connected to a resistance of 3.9 Ω. The voltage across the cell will be

Question

The internal resistance of a cell of e.m.f. 2 V is 0.1 Ω It is connected to a resistance of 3.9 Ω. The voltage across the cell will be (A) 1.95 V (B) 1.9 V (C) 0.5 V (D) 2 V

Tardigrade Admin · Accepted Answer

i=(2/4)=0.5 Ampere V= ε -ir or V = 2-0.5 × 0.1= 1.95 V

Q. The internal resistance of a cell of e.m.f. $2 V$ is $0.1 Ω$ It is connected to a resistance of $3.9 Ω$ . The voltage across the cell will be

1.95 V

1.9 V

0.5 V

2 V

$i = \frac{2}{4} = 0.5$ Ampere
$V = ε - i r$
or $V = 2 - 0.5 \times 0.1 = 1.95 V$

Q. The internal resistance of a cell of e.m.f. 2V is 0.1Ω It is connected to a resistance of 3.9Ω. The voltage across the cell will be

1.95 V

1.9 V

0.5 V

2 V

i=42​=0.5 Ampere V=ε−ir or V=2−0.5×0.1=1.95V

Q. The internal resistance of a cell of e.m.f. $2 V$ is $0.1 Ω$ It is connected to a resistance of $3.9 Ω$ . The voltage across the cell will be

$i = \frac{2}{4} = 0.5$ Ampere
$V = ε - i r$
or $V = 2 - 0.5 \times 0.1 = 1.95 V$