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Tardigrade
Question
Physics
The internal resistance of a 2.1 V cell which gives a current of 0.2 A through a resistance of 10Ω is
Q. The internal resistance of a
2.1
V
cell which gives a current of
0.2
A
through a resistance of
10Ω
is
5649
204
NEET
NEET 2013
Current Electricity
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A
1.0
Ω
13%
B
0.2
Ω
12%
C
0.5
Ω
66%
D
0.8
Ω
9%
Solution:
I
=
R
+
r
E
0.2
×
(
10
+
r
)
=
2.1
10
+
r
=
2
2.1
×
10
r
=
10.5
−
10
=
0.5Ω