Q. The internal resistance of a $2.1\, V$ cell which gives a current of $0.2\, A$ through a resistance of $10\Omega$ is
Solution:
$I =\frac{ E }{ R + r } $
$0.2 \times(10+ r )=2.1 $
$10+ r =\frac{2.1}{2} \times 10 $
$r =10.5-10=0.5 \Omega$
