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Tardigrade
Question
Physics
The internal energy change in a system that has absorbed 2 kcal of heat and done 500 J of work is
Q. The internal energy change in a system that has absorbed
2
k
c
a
l
of heat and done
500
J
of work is
5486
210
AIPMT
AIPMT 2009
Thermodynamics
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A
6400J
11%
B
5400J
15%
C
7900J
58%
D
8900J
16%
Solution:
Heat energy given
d
Q
=
d
U
+
d
W
where
d
U
is the change in internal energy and
d
W
is the work done.
Given
d
Q
=
2
k
c
a
l
=
2000
×
4.2
J
and
d
W
=
500
J
∴
d
Q
=
2000
×
4.2
=
d
U
+
500
⇒
d
U
=
7900
J