The internal and external diameters of a hollow cylinder are measured with the help of vernier callipers. Their values are 4.23±0.01cm and 3.87±0.01cm respectively. The thickness of the wall of the cylinder is

Question

The internal and external diameters of a hollow cylinder are measured with the help of vernier callipers. Their values are 4.23±0.01cm and 3.87±0.01cm respectively. The thickness of the wall of the cylinder is (A) 0.36 ± 0.02 cm (B) 0.18 ± 0.02cm (C) 0.36 ± 0.01cm (D) 0.18 ± 0.01cm

Tardigrade Admin · Accepted Answer

t=(D1 - D2/2)=(4 .23 - 3 .87/2)=0.18 text cm Δ t=Δ D1+Δ D2 =0.01+0.01=0.02 textcm ⇒ t=(. 0 .18 ± 0 .02 .) textcm

Q. The internal and external diameters of a hollow cylinder are measured with the help of vernier callipers. Their values are $4.23 \pm 0.01 c m$ and $3.87 \pm 0.01 c m$ respectively. The thickness of the wall of the cylinder is

$0.36 \pm 0.02 c m$

$0.18 \pm 0.02 c m$

$0.36 \pm 0.01 c m$

$0.18 \pm 0.01 c m$

$t = \frac{D _{1} - D _{2}}{2} = \frac{4.23 - 3.87}{2} = 0.18 cm$
$Δ t = Δ D_{1} + Δ D_{2}$
$= 0.01 + 0.01 = 0.02 cm$
$\Rightarrow t = (0.18 \pm 0.02) cm$

Q. The internal and external diameters of a hollow cylinder are measured with the help of vernier callipers. Their values are 4.23±0.01cm and 3.87±0.01cm respectively. The thickness of the wall of the cylinder is

0.36±0.02cm

0.18±0.02cm

0.36±0.01cm

0.18±0.01cm