The intensity ratio of two coherent sources of light is p. They are interfering in some region and produce interference pattern. Then the fringe visibility is

Question

The intensity ratio of two coherent sources of light is p. They are interfering in some region and produce interference pattern. Then the fringe visibility is (A) (1+p/2 √p) (B) (2 √p/1+p) (C) (p/1+p) (D) (2 p/1+p)

Tardigrade Admin · Accepted Answer

Visibility V=(I max -I min /I max +I min )=(2 √I1 I2/(I1+I2)) =(2 √I1 / I2/((I1)I2+1))=(2 √P/(P+1))

Q. The intensity ratio of two coherent sources of light is $p$ . They are interfering in some region and produce interference pattern. Then the fringe visibility is

$\frac{1 + p}{2 p}$

$\frac{2 p}{1 + p}$

$\frac{p}{1 + p}$

$\frac{2 p}{1 + p}$

Visibility $V = \frac{I _{m a x} - I _{m i n}}{I _{m a x} + I _{m i n}} = \frac{2 I _{1} I _{2}}{( I _{1} + I _{2} )}$
$= \frac{2 I _{1} / I _{2}}{( \frac{I _{1}}{I _{2}} + 1 )} = \frac{2 P}{( P + 1 )}$

Q. The intensity ratio of two coherent sources of light is p. They are interfering in some region and produce interference pattern. Then the fringe visibility is

2p​1+p​

1+p2p​​

1+pp​

1+p2p​

Visibility V=Imax​+Imin​Imax​−Imin​​=(I1​+I2​)2I1​I2​​​ =(I2​I1​​+1)2I1​/I2​​​=(P+1)2P​​

Q. The intensity ratio of two coherent sources of light is $p$ . They are interfering in some region and produce interference pattern. Then the fringe visibility is

$\frac{1 + p}{2 p}$

$\frac{2 p}{1 + p}$

$\frac{p}{1 + p}$

$\frac{2 p}{1 + p}$

Visibility $V = \frac{I _{m a x} - I _{m i n}}{I _{m a x} + I _{m i n}} = \frac{2 I _{1} I _{2}}{( I _{1} + I _{2} )}$
$= \frac{2 I _{1} / I _{2}}{( \frac{I _{1}}{I _{2}} + 1 )} = \frac{2 P}{( P + 1 )}$