The intensity of the magnetic induction field at the centre of a single turn circular coil of radius 5 cm carrying current of 0.9 A.

Question

The intensity of the magnetic induction field at the centre of a single turn circular coil of radius 5 cm carrying current of 0.9 A. (A) 36 π × 10-7 T (B) 9 π × 10-7 T (C) 36 π × 10-6 T (D) 9 π × 10-6 T

Tardigrade Admin · Accepted Answer

The intensity of magnetic induction field B =(μ0 i/2 r) =(4 π × 10-7 × 0.9/2 × 5 × 10-2) B =36 π × 10-7 T

Q. The intensity of the magnetic induction field at the centre of a single turn circular coil of radius $5 c m$ carrying current of $0.9 A$ .

$36 π \times 1 0^{- 7} T$

$9 π \times 1 0^{- 7} T$

$36 π \times 1 0^{- 6} T$

$9 π \times 1 0^{- 6} T$

The intensity of magnetic induction field
$B = \frac{μ _{0} i}{2 r}$
$= \frac{4 π \times 1 0 ^{- 7} \times 0.9}{2 \times 5 \times 1 0 ^{- 2}}$
$B = 36 π \times 1 0^{- 7} T$

Q. The intensity of the magnetic induction field at the centre of a single turn circular coil of radius 5cm carrying current of 0.9A.

36π×10−7T

9π×10−7T

36π×10−6T

9π×10−6T