Question

The instantaneous velocity of point $B$ of the given rod of length $0.5m$ is $3m{s}^{-1}$ in the represented direction. What is the angular velocity (in $rad{s}^{-1}$ ) of the rod for the minimum possible magnitude of the velocity of the end $A$ ? (Take $\sqrt{3}=1.7$ )

Answer 1

Answer: 5.2

If rod is rotated about end A, then vertical component of velocity, $v_{\perp }$ of end a will be zero.

$\therefore \omega =\frac{vsin60^o}{l}=\frac{\sqrt{3}v}{2l}$
$=\frac{\sqrt{3}\times 3}{2\times 0.5}=5.2$ $rad{s}^{-1}$