The inner and outer radius of a toroid core are 28 cm and 29 cm respectively and around the core 3700 turns of a wire are wounded. If the current in the wire is 10 A, then the magnetic field inside the core of the toroid is

Question

The inner and outer radius of a toroid core are 28 cm and 29 cm respectively and around the core 3700 turns of a wire are wounded. If the current in the wire is 10 A, then the magnetic field inside the core of the toroid is (A) 2.60 × 10-2 T (B) 2.60 × 10-3 T (C) 4.52 × 10-2 T (D) 4.52 × 10-3 T

Tardigrade Admin · Accepted Answer

The number of turns per unit length for the given toroid n=(N/2π rav) The average radius of toroid rav=(28+29/2)=28.5 cm =28.5×10-2 m ∴ n=(3700/2×3.14×28.5×10-2) =2067.27 ≈2067 Now, B=μ0nI=4π×10-7×2067×10 =259615.2×10-7 T =2.60×10-2 T

Q. The inner and outer radius of a toroid core are $28 c m$ and $29 c m$ respectively and around the core $3700$ turns of a wire are wounded. If the current in the wire is $10 A$ , then the magnetic field inside the core of the toroid is

$2.60 \times 1 0^{- 2} T$

$2.60 \times 1 0^{- 3} T$

$4.52 \times 1 0^{- 2} T$

$4.52 \times 1 0^{- 3} T$

Q. The inner and outer radius of a toroid core are 28cm and 29cm respectively and around the core 3700 turns of a wire are wounded. If the current in the wire is 10A, then the magnetic field inside the core of the toroid is

2.60×10−2T

2.60×10−3T

4.52×10−2T

4.52×10−3T

The number of turns per unit length for the given toroid n=2πrav​N​ The average radius of toroid rav​=228+29​=28.5cm =28.5×10−2m ∴n=2×3.14×28.5×10−23700​ =2067.27≈2067 Now, B=μ0​nI=4π×10−7×2067×10 =259615.2×10−7T =2.60×10−2T

Q. The inner and outer radius of a toroid core are $28 c m$ and $29 c m$ respectively and around the core $3700$ turns of a wire are wounded. If the current in the wire is $10 A$ , then the magnetic field inside the core of the toroid is

$2.60 \times 1 0^{- 2} T$

$2.60 \times 1 0^{- 3} T$

$4.52 \times 1 0^{- 2} T$

$4.52 \times 1 0^{- 3} T$