Q.
The initial temperature of a body is 80∘C. If its temperature falls to 64∘C in 5 minutes and in 10 minutes to 52∘. Find the temperature of surrounding.
According to Newton's law tθ1−θ2=k[2θ1+θ2−θ0]
Initially, 5(80−64)=K(280+64−θ0). ⇒3.2=K[72−θ0] ...(i)
Finally, 10(64−52)=K[264+52−θ0] ⇒1.2=K[58−θ0] ...(ii)
On solving equation
(i) and (ii) θ0=49∘C