The initial pressure of COCl 2 is 1000 torr. The total pressure of the system becomes 1500 torr, when the equilibrium COCl 2( g ) leftharpoons CO ( g )+ Cl 2( g ) is attained at constant temperature. The value of K p of a reaction

Question

The initial pressure of COCl 2 is 1000 torr. The total pressure of the system becomes 1500 torr, when the equilibrium COCl 2( g ) leftharpoons CO ( g )+ Cl 2( g ) is attained at constant temperature. The value of K p of a reaction (A) 1500 (B) 1000 (C) 2500 (D) 500

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/377642870e38bba645ae6cb5f920926f-.png" /> ∴ P text total =1000+P=1500 ⇒ P=500 torr ⇒ P=500 KP = (P2/1000 - P) = (500 × 500/500) = 500

Q. The initial pressure of $COC l_{2}$ is $1000$ torr. The total pressure of the system becomes $1500$ torr, when the equilibrium $COC l_{2} (g) ⇌ CO (g) + C l_{2} (g)$ is attained at constant temperature. The value of $K_{p}$ of a reaction

1500

1000

2500

500

$∴ P_{total} = 1000 + P = 1500$
$\Rightarrow P = 500$ torr
$\Rightarrow P = 500$
$K_{P} = \frac{P ^{2}}{1000 - P}$
$= \frac{500 \times 500}{500} = 500$

Q. The initial pressure of COCl2​ is 1000 torr. The total pressure of the system becomes 1500 torr, when the equilibrium COCl2​(g)⇌CO(g)+Cl2​(g) is attained at constant temperature. The value of Kp​ of a reaction

1500

1000

2500

500

∴Ptotal ​=1000+P=1500 ⇒P=500 torr ⇒P=500 KP​=1000−PP2​ =500500×500​=500

Q. The initial pressure of $COC l_{2}$ is $1000$ torr. The total pressure of the system becomes $1500$ torr, when the equilibrium $COC l_{2} (g) ⇌ CO (g) + C l_{2} (g)$ is attained at constant temperature. The value of $K_{p}$ of a reaction

$∴ P_{total} = 1000 + P = 1500$
$\Rightarrow P = 500$ torr
$\Rightarrow P = 500$
$K_{P} = \frac{P ^{2}}{1000 - P}$
$= \frac{500 \times 500}{500} = 500$