The induced emf in the loop, if the long wire carries a current of 50 A and the loop has an instantaneous velocity v=10 m / s at the location x=0.2 m as shown in figure is ε microvolt. Caluclate 3 ε. (Take a=0.1 m )

Question

The induced emf in the loop, if the long wire carries a current of 50 A and the loop has an instantaneous velocity v=10 m / s at the location x=0.2 m as shown in figure is ε microvolt. Caluclate 3 ε. (Take a=0.1 m ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Induced emf in the loop =B1 v l-B2 v l =(B1-B2) v l=[(μ0 I/2 π x)-(μ0 I/2 π(x+ a))](v)(a) =(μ0 I/2 π)((a2 v/x(x+ a))) =(2 × 10-7 × 50 ×(0.1)2 × 10/0.2 × 0.3) =(50/3) μ V

Q. The induced emf in the loop, if the long wire carries a current of 50A and the loop has an instantaneous velocity v=10m/s at the location x=0.2m as shown in figure is ε microvolt. Caluclate 3ε. (Take a=0.1m )

Induced emf in the loop =B1​vl−B2​vl =(B1​−B2​)vl=[2πxμ0​I​−2π(x+a)μ0​I​](v)(a) =2πμ0​I​(x(x+a)a2v​) =0.2×0.32×10−7×50×(0.1)2×10​ =350​μV

Q. The induced emf in the loop, if the long wire carries a current of $50 A$ and the loop has an instantaneous velocity $v = 10 m / s$ at the location $x = 0.2 m$ as shown in figure is $ε$ microvolt. Caluclate $3 ε$ . (Take $a = 0.1 m$ )