The increasing order of reduction of alkyl halides with zinc and dilute HCl is

Question

The increasing order of reduction of alkyl halides with zinc and dilute HCl is (A) R-Cl < R - I < R-Br (B) R-Cl < R-Br < R-I (C) R - I < R - Br < R - Cl (D) R-Br < R - I < R-Cl

Tardigrade Admin · Accepted Answer

The increasing order of reduction of alkyl halides with zinc and dil.

H Cl

is

R — Cl < R — B r < R — I

As the size of the halogen increases down the group, the strength of

C — X

bond decreases, as a result, reactivity increases.

Q. The increasing order of reduction of alkyl halides with zinc and dilute $H Cl$ is

$R - Cl < R - I < R - B r$

$R - Cl < R - B r < R - I$

$R - I < R - B r < R - Cl$

$R - B r < R - I < R - Cl$

The increasing order of reduction of alkyl halides with zinc and dil. $H Cl$ is
$R — Cl < R — B r < R — I$
As the size of the halogen increases down the group, the strength of $C — X$ bond decreases, as a result, reactivity increases.

Q. The increasing order of reduction of alkyl halides with zinc and dilute HCl is

R−Cl<R−I<R−Br

R−Cl<R−Br<R−I

R−I<R−Br<R−Cl

R−Br<R−I<R−Cl