The increasing order of reducing power of the halogen acids is

Question

The increasing order of reducing power of the halogen acids is (A) HF < HCl < HBr < HI (B) HI < HBr < HCl < HF (C) HBr < HCl < HF < HI (D) HCl < HBr < HF < HI

Tardigrade Admin · Accepted Answer

As the size of halogen atom increases, the bond strength of H-X bond decreases so tendency to give hydrogen increases resulting in increase in the reducing power. So increasing order is
HF < HCl < HBr < HI

Q. The increasing order of reducing power of the halogen acids is

HF < HCl < HBr < HI

HI < HBr < HCl < HF

HBr < HCl < HF < HI

HCl < HBr < HF < HI

As the size of halogen atom increases, the bond strength of H-X bond decreases so tendency to give hydrogen increases resulting in increase in the reducing power. So increasing order is HF < HCl < HBr < HI

As the size of halogen atom increases, the bond strength of H-X bond decreases so tendency to give hydrogen increases resulting in increase in the reducing power. So increasing order is
HF < HCl < HBr < HI