The increasing order of reactivity in the SN2 hydrolysis of the following alkylbromides is (1) tert-Butyl bromide (2) Methyl bromide (3) sec-Butyl bromide (4) n - Propyl bromide

Question

The increasing order of reactivity in the SN2 hydrolysis of the following alkylbromides is (1) tert-Butyl bromide (2) Methyl bromide (3) sec-Butyl bromide (4) n - Propyl bromide (A)  (1) < (3) < (4) < (2)  (B)  (2) < (4) < (3) < (1)  (C)  (1) < (4) < (3) < (2)  (D)  (2) < (3) < (4) < (1)

Tardigrade Admin · Accepted Answer

Reactivity order in SN2 reaction will be 1°> 2°> 3° More bulky substrates are least reactive in SN2 reactions

Therefore, order of reactivity is (1) < (3) < (4) < (2)

Q. The increasing order of reactivity in the $S_{N} 2$ hydrolysis of the following alkylbromides is
(1) $t er t$ -Butyl bromide
(2) Methyl bromide
(3) $sec$ -Butyl bromide
(4) $n$ - Propyl bromide

$(1) < (3) < (4) < (2)$

$(2) < (4) < (3) < (1)$

$(1) < (4) < (3) < (2)$

$(2) < (3) < (4) < (1)$

Reactivity order in $S_{N} 2$ reaction will be
$1^{\circ} > 2^{\circ} > 3^{\circ}$
More bulky substrates are least reactive in $S_{N} 2$ reactions

Therefore, order of reactivity is
$(1) < (3) < (4) < (2)$

Q. The increasing order of reactivity in the SN​2 hydrolysis of the following alkylbromides is (1) tert-Butyl bromide (2) Methyl bromide (3) sec-Butyl bromide (4) n - Propyl bromide

(1)<(3)<(4)<(2)

(2)<(4)<(3)<(1)

(1)<(4)<(3)<(2)

(2)<(3)<(4)<(1)