The increasing order of PKb for the following compounds will be (.1.) NH2-CH=NH, (.2.) (.3.) CH3NHCH3

Question

The increasing order of PKb for the following compounds will be (.1.) NH2-CH=NH, (.2.) <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/c-ox7ivmnnkhe5ancz.jpg" /> (.3.) CH3NHCH3 (A) (.2.) < (.1.) < (.3.) (B) (.3.) < (.1.) < (.2.) (C) (.2.) < (.3.) < (.1.) (D) (.1.) < (.2.) < (.3.)

Tardigrade Admin · Accepted Answer

pKb propto (1/Kb) propto (1/B a s i c s t r e n g t h) As basic nature decreases in the order (2) > (1) > (3). So pKb order is as follows (.2.) < (.1.) < (.3.)

Q. The increasing order of $P K_{b}$ for the following compounds will be
$(1)$ $N H_{2} - C H = N H,$
$(2)$
$(3)$ $C H_{3} N H C H_{3}$

$(2) < (1) < (3)$

$(3) < (1) < (2)$

$(2) < (3) < (1)$

$(1) < (2) < (3)$

$p K_{b} \propto \frac{1}{K _{b}} \propto \frac{1}{B a s i c s t re n g t h}$
As basic nature decreases in the order (2) > (1) > (3). So $p K_{b}$ order is as follows
$(2) < (1) < (3)$

Q. The increasing order of PKb​ for the following compounds will be (1) NH2​−CH=NH, (2) (3) CH3​NHCH3​

(2)<(1)<(3)

(3)<(1)<(2)

(2)<(3)<(1)

(1)<(2)<(3)