The increasing order of acidity is

Question

The increasing order of acidity is (A)  CHCl2COOH<CH2ClCOOH<CH3COOH  (B)  CH3COOH<CHCl2COOH<CH2ClCOOH  (C)  CH2BrCOOH<CH2ClCOOH<CH2ClCOOH  (D)  CH2BrCOOH<CH2ClCOOH<CHCl2COOH

Tardigrade Admin · Accepted Answer

The acidity of halogen acids depends upon the number, nature and position of halogen atom. Greater the electron withdrawing influence of halogen atom, stronger will be the acid. Moreover, with increase in number of halogen atoms acidic strength also increases. Thus, the increasing order of acidity is CH2BrCOOH<CH2ClCOOH<CHCl2COOH

Q. The increasing order of acidity is

$C H C l_{2} COO H < C H_{2} ClCOO H < C H_{3} COO H$

$C H_{3} COO H < C H C l_{2} COO H < C H_{2} ClCOO H$

$C H_{2} B r COO H < C H_{2} ClCOO H < C H_{2} ClCOO H$

$C H_{2} B r COO H < C H_{2} ClCOO H < C H C l_{2} COO H$

Q. The increasing order of acidity is

CHCl2​COOH<CH2​ClCOOH<CH3​COOH

CH3​COOH<CHCl2​COOH<CH2​ClCOOH

CH2​BrCOOH<CH2​ClCOOH<CH2​ClCOOH

CH2​BrCOOH<CH2​ClCOOH<CHCl2​COOH

$C H C l_{2} COO H < C H_{2} ClCOO H < C H_{3} COO H$

$C H_{3} COO H < C H C l_{2} COO H < C H_{2} ClCOO H$

$C H_{2} B r COO H < C H_{2} ClCOO H < C H_{2} ClCOO H$

$C H_{2} B r COO H < C H_{2} ClCOO H < C H C l_{2} COO H$