The increase in length on stretching a wire is 0.05%. If its Poissons ratio is 0.4, then its diameter will be

Question

The increase in length on stretching a wire is 0.05%. If its Poissons ratio is 0.4, then its diameter will be (A) reduced by 0.02% (B) reduced by 0.1% (C) increased by 0.02% (D) decreased by 0.4%

Tardigrade Admin · Accepted Answer

Poissons ratio =(Lateral strain/Longitudinal strain) ∴ Lateral strain =0.4× (0.5/100) So reduced by ~0.02% .

Q. The increase in length on stretching a wire is 0.05%. If its Poissons ratio is 0.4, then its diameter will be

reduced by 0.02%

reduced by 0.1%

increased by 0.02%

decreased by 0.4%

Poissons ratio $= \frac{L a t er a l s t r ain}{L o n g i t u d ina l s t r ain}$ $∴$ Lateral strain $= 0.4 \times \frac{0.5}{100}$ So reduced by $0.02$ .

Q. The increase in length on stretching a wire is 0.05%. If its Poissons ratio is 0.4, then its diameter will be

reduced by 0.02%

reduced by 0.1%

increased by 0.02%

decreased by 0.4%

Poissons ratio =LongitudinalstrainLateralstrain​ ∴ Lateral strain =0.4×1000.5​ So reduced by 0.02 .

Poissons ratio $= \frac{L a t er a l s t r ain}{L o n g i t u d ina l s t r ain}$ $∴$ Lateral strain $= 0.4 \times \frac{0.5}{100}$ So reduced by $0.02$ .