The increase in length of a wire on stretching is 0.025 %. If its Poisson's ratio is 0.4, then the percentage decrease in diameter is

Question

The increase in length of a wire on stretching is 0.025 %. If its Poisson's ratio is 0.4, then the percentage decrease in diameter is (A) 0.01 % (B) 0.02 % (C) 0.03 % (D) 0.04 %

Tardigrade Admin · Accepted Answer

% decrease in diameter =(Δ D/D) × 100 %=σ((Δ l/l)) × 100 % (Using (i)) =0.4 × (0.025/100) × 100 % =0.01 %

Q. The increase in length of a wire on stretching is $0.025%$ . If its Poisson's ratio is $0.4$ , then the percentage decrease in diameter is

$0.01%$

$0.02%$

$0.03%$

$0.04%$

$%$ decrease in diameter
$= \frac{Δ D}{D} \times 100% = σ (\frac{Δ l}{l}) \times 100%$ (Using (i))
$= 0.4 \times \frac{0.025}{100} \times 100%$
$= 0.01%$

Q. The increase in length of a wire on stretching is 0.025%. If its Poisson's ratio is 0.4, then the percentage decrease in diameter is

0.01%

0.02%

0.03%

0.04%