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Physics
The increase in length of a wire on stretching is 0.025 %. If its Poisson's ratio is 0.4, then the percentage decrease in diameter is
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Q. The increase in length of a wire on stretching is $0.025 \%$. If its Poisson's ratio is $0.4$, then the percentage decrease in diameter is
Mechanical Properties of Solids
A
$0.01 \%$
B
$0.02 \%$
C
$0.03 \%$
D
$0.04 \%$
Solution:
$ \%$ decrease in diameter
$=\frac{\Delta D}{D} \times 100 \%=\sigma\left(\frac{\Delta l}{l}\right) \times 100 \%$ (Using (i))
$=0.4 \times \frac{0.025}{100} \times 100 \%$
$=0.01 \%$