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Tardigrade
Question
Mathematics
The imaginary part of ii is
Q. The imaginary part of
i
i
is
3839
215
KCET
KCET 2007
Complex Numbers and Quadratic Equations
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A
1
30%
B
0
39%
C
-1
25%
D
2
5%
Solution:
Let
(
a
+
ib
)
=
i
i
Taking log on both sides, we get
lo
g
(
a
+
ib
)
=
i
lo
g
i
⇒
lo
g
(
a
+
ib
)
=
i
(
i
π
/2
)
⇒
lo
g
(
a
+
ib
)
=
−
2
π
⇒
(
a
+
ib
)
=
e
−
π
/2
On comparing imaginary part of
i
i
is 0.