Any point on the given line is (2t, 2 + 3t, 3 + 4t) .
it is the foot of perpendicular from (3, -1, 11)
if (2t−3)×2+(2+3t+1)×3+(3+4t−11)×4=0 ⇒t=1
So, the coordinates of foot of perpendicular are (2, 5, 7)
Now, the point (a, b, c) will be the image of the point (3, -1, 11) in the given line if 23+a=2,2b−1=5; 2c+11=7⇒a=1,b=11,c=3