The hydrolysis of ethyl acetate, CH3COOC2H5+H2O -[H+] CH3COOH+C2H5OH is a reaction of

Question

The hydrolysis of ethyl acetate, CH3COOC2H5+H2O ->[H+] CH3COOH+C2H5OH is a reaction of (A) zero order (B) pseudo first order (C) second order (D) third order.

Tardigrade Admin · Accepted Answer

A reaction which is not the first-order reaction naturally but made the first order by increasing or decreasing the concentration of one or the other reactant is known as Pseudo first-order reaction.
Hydrolysis of ethyl acetate in presence of an excess of water:

C H_{3} COO C_{2} H_{5} + H_{2} O

(excess)

H + C H_{3} COO H + C_{2} H_{5} O H

r = k [C H_{3} COO C_{2} H_{5}]^{2} [H_{2} O]^{0}

Excess

[H_{2} O]

can cause the independency of reaction on

H_{2} O

.
Hence, it is a pseudo-first-order reaction.

Q. The hydrolysis of ethyl acetate, CH3​COOC2​H5​+H2​O HX+​ CH3​COOH+C2​H5​OH is a reaction of

zero order

pseudo first order

second order

third order.

Q. The hydrolysis of ethyl acetate,
$C H_{3} COO C_{2} H_{5} + H_{2} O$ $H X^{+}$ $C H_{3} COO H + C_{2} H_{5} O H$ is a reaction of