Question

The hybridized state of $A{l}^{3+}$ in the complex ion formed when $AlC{l}_3$ is treated with aqueous acid is

• A. $s{p}^3$
• B. $ds{p}^2$
• C. $s{p}^3{d}^2$
• D. $s{p}^{2}d$
• E. $s{p}^2$

Answer 1

Answer: (C)

$AlC{l}_3+$ aqueous acid $\to {\left[Al{\left(H_{2}O\right)}_6\right]}^{3+}$

$A{l}^{3+}$ ions give a complex ion in which $A{l}^{3+}$ ion form six coordinate covalent bonds with six $H_{2}O$ molecules. Hence, it shows $s{p}^3{d}^2$ hybridisation.

(Due to availability of vacant $3d$ -orbitals.)

$Al=3s^{2}3p^1$

$A{l}^{3T}=3s^0$



Four electron pairs denoted by $6H_{2}O$ molecules