Question

The hybridization involved in $PC{l}_5$ is

• A. $s{p}^{3}d$
• B. $s{p}^3{d}^2$
• C. $d^{2}s{p}^2$
• D. $s{p}^3$

Answer 1

Answer: (A)

In $PC{l}_5$ five chlorine atoms directly attached to central atom and it has no Ione pairs and no single electrons hence $PC{l}_5$ has $s{p}^{3}d$ hybridization.