The hybridisation, oxidation number of central metal ion and shape of Wilkinson's catalyst are

Question

The hybridisation, oxidation number of central metal ion and shape of Wilkinson's catalyst are (A) d s p2,+1, square planar (B) s p3,+4, tetrahedral (C) s p3 d,+2, trigonal bipyramidal (D) d2 s p3,+6, octahedral.

Tardigrade Admin · Accepted Answer

In Wilkinson's catalyst-(a homogeneous catalyst), ( Ph 3 P )3 Rh Cl , Rh is d s p2 hybridised giving a square planar shape to the compound and is in +1 oxidation state.

Q. The hybridisation, oxidation number of central metal ion and shape of Wilkinson's catalyst are

$d s p^{2}, + 1,$ square planar

$s p^{3}, + 4,$ tetrahedral

$s p^{3} d, + 2,$ trigonal bipyramidal

$d^{2} s p^{3}, + 6,$ octahedral.

In Wilkinson's catalyst-(a homogeneous catalyst), $(P h_{3} P)_{3} R h Cl, R h$ is $d s p^{2}$ hybridised giving a square planar shape to the compound and is in $+ 1$ oxidation state.

Q. The hybridisation, oxidation number of central metal ion and shape of Wilkinson's catalyst are

dsp2,+1, square planar

sp3,+4, tetrahedral

sp3d,+2, trigonal bipyramidal

d2sp3,+6, octahedral.

In Wilkinson's catalyst-(a homogeneous catalyst), (Ph3​P)3​RhCl,Rh is dsp2 hybridised giving a square planar shape to the compound and is in +1 oxidation state.

$d s p^{2}, + 1,$ square planar

$s p^{3}, + 4,$ tetrahedral

$s p^{3} d, + 2,$ trigonal bipyramidal

$d^{2} s p^{3}, + 6,$ octahedral.

In Wilkinson's catalyst-(a homogeneous catalyst), $(P h_{3} P)_{3} R h Cl, R h$ is $d s p^{2}$ hybridised giving a square planar shape to the compound and is in $+ 1$ oxidation state.