Question

The Hybridisation of atomic orbitals of nitrogen in ${\text{NO}}_2^{+}$ ${\text{, NO}}_3^{-}$ , and ${\text{NH}}_4^{+}$ are?

• A. sp² ,sp ,and sp³ Respectively.
• B. sp² , sp³ and sp Respectively
• C. sp , sp³ and sp² respectively.
• D. sp , sp² and sp³ respectively.

Answer 1

Answer: (D)

The number of hybrid orbitals $=H=\frac{1}{2}(V+M-C+A)$
V = number of valence electrons
M= number of monovalent atoms(H, X=F,Cl,Br,I etc)
C = number of units of positive charge
A= number of units of negative charge
${\text{NO}}_2^{+}\Rightarrow \text{H}=\frac{1}{2}\left(5-1\right)=2,$ sp Hybridisation.
${\text{NO}}_3^{-}\Rightarrow \text{H}=\frac{1}{2}\left(5+1\right)=3,$ sp² Hybridisation.
${\text{NH}}_4^{+}\Rightarrow \text{H}=\frac{1}{2}\left(5+4-1\right)=4,$ sp³ Hybridisation