Question

The hybridisation in $B{F}_3$ molecule is:

• A. $sp$
• B. $s{p}^2$
• C. $s{p}^3$
• D. $s{p}^{3}d$

Answer 1

Answer: (B)

In the formation of $B{F}_3$ molecule, one $s$ and $2p$ orbitals hybridise. Therefore, it is $s{p}^2$