The horizontal range of a projectile fired at an angle of 15° is 50 m. If it is fired with the same speed at an angle of 45°, its range will be

Question

The horizontal range of a projectile fired at an angle of 15° is 50 m. If it is fired with the same speed at an angle of 45°, its range will be (A) 60 m (B) 71 m (C) 100 m (D) 141 m

Tardigrade Admin · Accepted Answer

Horizontal range, R=(u2 sin 2θ/g) For the same speed, R propto sin 2θ ∴ (R1/R2)=(sin 2×15Â°/sin 2×45Â°) =(sin 30Â°/sin 90Â°) or R2=R1 (sin 90Â°/sin 30Â°) =50 m×(1/((1)2)) =100 m

Q. The horizontal range of a projectile fired at an angle of $1 5^{°}$ is $50 m$ . If it is fired with the same speed at an angle of $4 5^{°}$ , its range will be

$60 m$

$71 m$

$100 m$

$141 m$

Q. The horizontal range of a projectile fired at an angle of 15° is 50m. If it is fired with the same speed at an angle of 45°, its range will be

60m

71m

100m

141m

Horizontal range, R=gu2sin2θ​ For the same speed, R∝sin2θ ∴R2​R1​​=sin2×45°sin2×15°​ =sin90°sin30°​ or R2​=R1​sin30°sin90°​ =50m×(21​)1​ =100m

Q. The horizontal range of a projectile fired at an angle of $1 5^{°}$ is $50 m$ . If it is fired with the same speed at an angle of $4 5^{°}$ , its range will be

$60 m$

$71 m$

$100 m$

$141 m$