Question

The horizontal component of the earth's magnetic field is $0.22$ gauss and total magnetic field is $0.4$ gauss. The angle of dip is

• A. ${\tan }^{-1}(1)$
• B. ${\tan }^{-1}(\infty )$
• C. ${\tan }^{-1}(1.518)$
• D. ${\tan }^{-1}(\pi )$

Answer 1

Answer: (C)

By using $B_H=B\cos \varphi$
$\Rightarrow \cos \varphi =\frac{B_H}{B}=\frac{0.22}{0.4}$
$\Rightarrow \tan \varphi =\frac{\sqrt{(0.4{)}^2-(0.22{)}^2}}{0.22}$
$\Rightarrow \varphi ={\tan }^{-1}(1.518)$