Question

The horizontal component of the earth's magnetic field is $0.22$ gauss and total magnetic field is $0.4$ gauss. The angle of dip is

• A. $\tan ^{-1}(1)$
• B. $\tan ^{-1}(\infty)$
• C. $\tan ^{-1}(1.518)$
• D. $\tan ^{-1}(\pi)$

Answer 1

Answer: (C)

By using $B_{H}=B \cos \phi$
$\Rightarrow \cos \phi=\frac{B_{H}}{B}=\frac{0.22}{0.4}$
$\Rightarrow \tan \phi=\frac{\sqrt{(0.4)^{2}-(0.22)^{2}}}{0.22}$
$\Rightarrow \phi=\tan ^{-1}(1.518)$