The horizontal and vertical components of the initial velocity of a projectile are 10 m / s and 20 m / s, respectively. The horizontal range of the projectile will be [g=10 m / s 2]:-

Question

The horizontal and vertical components of the initial velocity of a projectile are 10 m / s and 20 m / s, respectively. The horizontal range of the projectile will be [g=10 m / s 2]:- (A) 5 m (B) 10 m (C) 20 m (D) 40 m

Tardigrade Admin · Accepted Answer

R =(2 u x u y / g )=(2 × 10 × 20/10)=40 m

Q. The horizontal and vertical components of the initial velocity of a projectile are $10 m / s$ and $20 m / s$ , respectively. The horizontal range of the projectile will be $[g = 10 m / s^{2}] : -$

5 m

10 m

20 m

40 m

$R = \frac{2 u _{x} u _{y}}{g} = \frac{2 \times 10 \times 20}{10} = 40 m$

Q. The horizontal and vertical components of the initial velocity of a projectile are 10m/s and 20m/s, respectively. The horizontal range of the projectile will be [g=10m/s2]:−

5 m

10 m

20 m

40 m

R=g2ux​uy​​=102×10×20​=40m

Q. The horizontal and vertical components of the initial velocity of a projectile are $10 m / s$ and $20 m / s$ , respectively. The horizontal range of the projectile will be $[g = 10 m / s^{2}] : -$

$R = \frac{2 u _{x} u _{y}}{g} = \frac{2 \times 10 \times 20}{10} = 40 m$