The height of liquid column raised in a capillary tube of certain radius when dipped in liquid A vertically is, 5 cm. If the tube is dipped in a similar manner in another liquid B of surface tension and density double the values of liquid A, the height of liquid column raised in liquid B would be m.

Question

The height of liquid column raised in a capillary tube of certain radius when dipped in liquid A vertically is, 5 cm. If the tube is dipped in a similar manner in another liquid B of surface tension and density double the values of liquid A, the height of liquid column raised in liquid B would be m. (A) 0.20 (B) 0.5 (C) 0.10 (D) 0.05

Tardigrade Admin · Accepted Answer

h =(2 S cos θ/ r ρ g ) ∴ ( h 1/ h 2) =( S 1/ S 2) (ρ2/ρ1) (5/ h 2) =[(1/2)][(2/1)] ⇒ h 2=5 cm =0.05 m Info about angle of contact not there so most appropriate is 3

$0.20$

$0.5$

$0.10$

$0.05$

$h = \frac{2 S c o s θ}{r ρ g}$
$∴ \frac{h _{1}}{h _{2}} = \frac{S _{1}}{S _{2}} \frac{ρ _{2}}{ρ _{1}}$
$\frac{5}{h _{2}} = [\frac{1}{2}] [\frac{2}{1}] \Rightarrow h_{2} = 5 c m = 0.05 m$
${$ Info about angle of contact not there so most appropriate is 3 $}$

0.20

0.5

0.10

0.05

h=rρg2Scosθ​ ∴h2​h1​​=S2​S1​​ρ1​ρ2​​ h2​5​=[21​][12​]⇒h2​=5cm=0.05m {Info about angle of contact not there so most appropriate is 3 }

$0.20$

$0.5$

$0.10$

$0.05$

$h = \frac{2 S c o s θ}{r ρ g}$
$∴ \frac{h _{1}}{h _{2}} = \frac{S _{1}}{S _{2}} \frac{ρ _{2}}{ρ _{1}}$
$\frac{5}{h _{2}} = [\frac{1}{2}] [\frac{2}{1}] \Rightarrow h_{2} = 5 c m = 0.05 m$
${$ Info about angle of contact not there so most appropriate is 3 $}$