The heats of neutralisation of HCl with NH4OH and NaOH with CH3COOH are respectively -51.4 and -50.6 kJ eq-1 The heat of neutralisation of acetic acid with NH4OH will be

Question

The heats of neutralisation of HCl with NH4OH and NaOH with CH3COOH are respectively -51.4 and -50.6 kJ eq-1 The heat of neutralisation of acetic acid with NH4OH will be (A) -44.6 kJ eq-1 (B) -50.6 kJ eq-1 (C) -51.4 kJ eq-1 (D) -57.4 kJ eq-1

Tardigrade Admin · Accepted Answer

(i) HCI + NH4OH arrow NH4Cl + H2O ; Δ H = -51.4 kJ (ii) CH3COOH + NaOH arrow CH3COONa + H2O ; Δ H = - 50.6 kJ (iii) CH3COOH + NH4OH arrow CH3COONH4 + H2O ; AH = ? We know (iv) HCl + NaOH arrow NaCl + H2O; Δ H = -57-4 kJ To get (iii) add (i) and (ii) and subtract (iv). (Please note that salts formed in case (i) and (ii) are almost completely ionised. Also suppose that the salt formed in case (iii) is also ionised). Δ H = (- 51.4) + (-50.6) - (-57.4) kJ = 51.4 - 50.6 + 57.4 = -44.6 kJ

Q. The heats of neutralisation of HCl with $N H_{4} O H$ and $N a O H$ with $C H_{3} COO H$ are respectively $- 51.4 an d - 50.6 k J e q^{- 1}$ The heat of neutralisation of acetic acid with $N H_{4} O H$ will be

$- 44.6 k J e q^{- 1}$

$- 50.6 k J e q^{- 1}$

$- 51.4 k J e q^{- 1}$

$- 57.4 k J e q^{- 1}$

Q. The heats of neutralisation of HCl with NH4​OH and NaOH with CH3​COOHare respectively −51.4and−50.6kJeq−1 The heat of neutralisation of acetic acid with NH4​OH will be

−44.6kJeq−1

−50.6kJeq−1

−51.4kJeq−1

−57.4kJeq−1

Q. The heats of neutralisation of HCl with $N H_{4} O H$ and $N a O H$ with $C H_{3} COO H$ are respectively $- 51.4 an d - 50.6 k J e q^{- 1}$ The heat of neutralisation of acetic acid with $N H_{4} O H$ will be

$- 44.6 k J e q^{- 1}$

$- 50.6 k J e q^{- 1}$

$- 51.4 k J e q^{- 1}$

$- 57.4 k J e q^{- 1}$