Question

The heat of neutralisation of a strong acid and a strong alkali is $57.0\text{kJ}\text{mo}{\text{l}}^{-1}.$ The heat released when $0.5mole$ of $\text{HN}{\text{O}}_{\text{3}}$ solution is mixed with $0.2mole$ of $KOH$ is

• A. 57.0 kJ
• B. 11.4 kJ
• C. 28.5 kJ
• D. 34.9 kJ

Answer 1

Answer: (B)

0.2 mole of KOH will neutralise 0.2 mole of
$\text{HN}{\text{O}}_{\text{3}}\text{.}$
Thus, heat evolved
$=57\times 0.2=11.4kJ$