Question

The heat of neutralisation of a strong acid and a strong alkali is $ 57.0\,\text{kJ}\,\text{mo}{{\text{l}}^{-1}}. $ The heat released when $0.5\, mole$ of $ \text{HN}{{\text{O}}_{\text{3}}} $ solution is mixed with $0.2\, mole$ of $KOH$ is

• A. 57.0 kJ
• B. 11.4 kJ
• C. 28.5 kJ
• D. 34.9 kJ

Answer 1

Answer: (B)

0.2 mole of KOH will neutralise 0.2 mole of
$ \text{HN}{{\text{O}}_{\text{3}}}\text{.} $
Thus, heat evolved
$ =57\times 0.2=11.4\text{ }kJ $