The heat of formation of C12H22O11(s),CO2(g) and H2O(l) are -530,-94.3 and -68.3 kcal mol-1 respectively. The amount of C12H22O11 to supply 2700 kcal of energy is

Question

The heat of formation of C12H22O11(s),CO2(g) and H2O(l) are -530,-94.3 and -68.3 kcal mol-1 respectively. The amount of C12H22O11 to supply 2700 kcal of energy is (A) 382.70 g (B) 832.74 g (C) 463.9 g (D) 684.0 g

Tardigrade Admin · Accepted Answer

C12H22O11(s)+12O2(g) xrightarrow[]12CO2(g)+11H2O(l) Δ Hcombo=[12Δ Hfo(CO2)]+11Δ Hfo(H2O] -Δ Hfo(C12H22O11)] =-1352.9 text kcal Thus, number of moles of C12H22O11 for getting 2700 kcal of heat =(2700/1352.9)=2 mol =2× 242=684g

Q. The heat of formation of C12​H22​O11​(s),CO2​(g) and H2​O(l) are −530,−94.3 and −68.3 kcal mol−1 respectively. The amount of C12​H22​O11​ to supply 2700 kcal of energy is

382.70 g

832.74 g

463.9 g

684.0 g

C12​H22​O11​(s)+12O2​(g)​12CO2​(g)+11H2​O(l) ΔHcombo​=[12ΔHfo​(CO2​)]+11ΔHfo​(H2​O] −ΔHfo​(C12​H22​O11​)] =−1352.9kcal Thus, number of moles of C12​H22​O11​ for getting 2700 kcal of heat =1352.92700​=2mol =2×242=684g

Q. The heat of formation of $C_{12} H_{22} O_{11} (s), C O_{2} (g)$ and $H_{2} O (l)$ are $- 530, - 94.3$ and $- 68.3$ kcal $m o l^{- 1}$ respectively. The amount of $C_{12} H_{22} O_{11}$ to supply 2700 kcal of energy is