Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The heat of combustion of solid benzoic acid at constant volume is -321.30 kJ at 27° C . The heat of combustion at constant pressure is
Q. The heat of combustion of solid benzoic acid at constant volume is
−
321.30
k
J
at
2
7
∘
C
. The heat of combustion at constant pressure is
12074
194
Uttarkhand PMT
Uttarkhand PMT 2008
Report Error
A
−
321.30
−
300
R
B
−
321.30
+
300
R
C
−
321.30
−
150
R
D
−
321.30
+
900
R
Solution:
C
6
H
5
COO
H
(
s
)
+
2
15
O
2
(
g
)
→
7
C
O
2
(
g
)
+
3
H
2
O
(
l
)
Δ
n
g
=
n
p
−
n
r
=
7
−
2
15
=
2
−
1
q
p
=
q
v
+
Δ
n
g
(
RT
)
=
−
321.30
+
(
−
2
1
)
300
R
=
−
321.30
−
150
R