The heat of combustion of ethane and benzene is -1560 and -3268 kj mol-1 respectively. Which of two has higher efficiency as fuel per gram and the amount of heat produced per gram?

Question

The heat of combustion of ethane and benzene is -1560 and -3268 kj mol-1 respectively. Which of two has higher efficiency as fuel per gram and the amount of heat produced per gram? (A) Benzene, 41.9 kj g-1 (B) Ethane, 52 kj g-1 (C) Benzene, 78 kj g-1 (D) Ethane, 30 kj g-1

Tardigrade Admin · Accepted Answer

Heat produced by ethane = (1560/30) = 52 kJ g-1 Heat produced by benzene = (3268/78)= 41.9 kJ g-1

Q. The heat of combustion of ethane and benzene is $- 1560$ and $- 3268 kj m o l^{- 1}$ respectively. Which of two has higher efficiency as fuel per gram and the amount of heat produced per gram?

Benzene, $41.9 kj g^{- 1}$

Ethane, $52 kj g^{- 1}$

Benzene, $78 kj g^{- 1}$

Ethane, $30 kj g^{- 1}$

Heat produced by ethane $= \frac{1560}{30} = 52 k J g^{- 1}$
Heat produced by benzene $= \frac{3268}{78} = 41.9 k J g^{- 1}$

Q. The heat of combustion of ethane and benzene is −1560 and −3268kjmol−1 respectively. Which of two has higher efficiency as fuel per gram and the amount of heat produced per gram?

Benzene, 41.9kjg−1

Ethane, 52kjg−1

Benzene, 78kjg−1

Ethane, 30kjg−1