The heat flows through a rod of length 50 cm and area of cross-section 5 cm 2. Its ends are respectively at 25° C and 125° C. The coefficient of thermal conductivity of the material rod is 0.092 kcal / m ° C. The temperature gradient of the rod is

Question

The heat flows through a rod of length 50 cm and area of cross-section 5 cm 2. Its ends are respectively at 25° C and 125° C. The coefficient of thermal conductivity of the material rod is 0.092 kcal / m ° C. The temperature gradient of the rod is (A) 2° C / cm (B) 2° C / m (C) 20° C / cm (D) 20° C / m

Tardigrade Admin · Accepted Answer

Temperature gradient of the rod (Δ θ/Δ x)=(θ2-θ1/l) ∴ (Δ θ/Δ x) =(125-25/50) =(100/50)=2° C / cm

Q. The heat flows through a rod of length $50 c m$ and area of cross-section $5 c m^{2}$ . Its ends are respectively at $2 5^{\circ} C$ and $12 5^{\circ} C$ . The coefficient of thermal conductivity of the material rod is $0.092 k c a l / m^{\circ} C$ . The temperature gradient of the rod is

$2^{\circ} C / c m$

$2^{\circ} C / m$

$2 0^{\circ} C / c m$

$2 0^{\circ} C / m$

Temperature gradient of the rod
$\frac{Δ θ}{Δ x} = \frac{θ _{2} - θ _{1}}{l}$
$∴ \frac{Δ θ}{Δ x} = \frac{125 - 25}{50}$
$= \frac{100}{50} = 2^{\circ} C / c m$

Q. The heat flows through a rod of length 50cm and area of cross-section 5cm2. Its ends are respectively at 25∘C and 125∘C. The coefficient of thermal conductivity of the material rod is 0.092kcal/m∘C. The temperature gradient of the rod is

2∘C/cm

2∘C/m

20∘C/cm

20∘C/m