The heat energy absorbed by a system in going through a cyclic process shown in figure is :

Question

The heat energy absorbed by a system in going through a cyclic process shown in figure is : (A) 107 π J (B) 104 π J (C) 102 π J (D) 103 π J

Tardigrade Admin · Accepted Answer

Work done is equal to area of loop. In a cyclic process, heat energy absorbed is equal to work done as change in internal energy of the system is zero.
Work done is equal to area of loop. Radius of loop

= \frac{30 - 10}{2} = 10

∴

Area

= π r^{2}

= π (10)^{2}

= 100 π = 1 0^{2} π J

Hence, required work done

= 1 0^{2} π J

.

Q. The heat energy absorbed by a system in going through a cyclic process shown in figure is :

$1 0^{7} π J$

$1 0^{4} π J$

$1 0^{2} π J$

$1 0^{3} π J$

Q. The heat energy absorbed by a system in going through a cyclic process shown in figure is :

107πJ

104πJ

102πJ

103πJ

Work done is equal to area of loop. In a cyclic process, heat energy absorbed is equal to work done as change in internal energy of the system is zero. Work done is equal to area of loop. Radius of loop =230−10​=10 ∴ Area =πr2 =π(10)2 =100π=102πJ Hence, required work done =102πJ.

$1 0^{7} π J$

$1 0^{4} π J$

$1 0^{2} π J$

$1 0^{3} π J$