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  4. The heat energy absorbed by a system in going through a cyclic process shown in figure is :

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Q. The heat energy absorbed by a system in going through a cyclic process shown in figure is :Physics Question Image

BHUBHU 2002

Solution:

Work done is equal to area of loop. In a cyclic process, heat energy absorbed is equal to work done as change in internal energy of the system is zero.
Work done is equal to area of loop. Radius of loop
$=\frac{30-10}{2}=10 $
$\therefore $ Area $=\pi\, r^{2}$
$=\pi(10)^{2} $
$=100 \pi=10^{2} \,\pi \,J$
Hence, required work done $=10^{2} \,\pi \,J$.