The heat capacity per mole of water is (R is universal gas constant)

Question

The heat capacity per mole of water is (R is universal gas constant) (A)  9R  (B)  (9/2)R  (C)  6R  (D)  5R

Tardigrade Admin · Accepted Answer

Molar specific heat of water = molar mass of water × specific heat of water =(18g/mol)× (1 cal/goC) =18(cal/moloC) =9R [where, R=2 text cal text mol-2o text C-1 ]

Q. The heat capacity per mole of water is ( $R$ is universal gas constant)

$9 R$

$\frac{9}{2} R$

$6 R$

$5 R$

$3 R$

Molar specific heat of water = molar mass of water
$\times$ specific heat of water
$= \frac{18 g}{m o l} \times \frac{1 c a l}{g ^{o} C}$
$= 18 \frac{c a l}{m o l ^{o} C}$
$= 9 R$ [where, $R = 2 c a l m o l^{- 2_{o}} C^{- 1}$ ]

Q. The heat capacity per mole of water is (R is universal gas constant)

9R

29​R

6R

5R

3R

Molar specific heat of water = molar mass of water × specific heat of water =mol18g​×goC1cal​ =18moloCcal​ =9R [where, R=2calmol−2o​C−1 ]