The HCF of two polynomials A and B using long division method was found to be 2 x+1 after two steps. The first two quotients obtained are x and (x+1). Find A and B. Given that degree of A degree of B.

Question

The HCF of two polynomials A and B using long division method was found to be 2 x+1 after two steps. The first two quotients obtained are x and (x+1). Find A and B. Given that degree of A> degree of B. (A) A=2 x3+3 x2+x-1, B=2 x2-3 x+1 (B) A=2 x3-3 x2+x-1, B=2 x2-3 x-1 (C) A=2 x3+3 x2-3 x-1, B=2 x2-3 x+1 (D) A=2 x3+3 x2+3 x+1, B=2 x2+3 x+1

Tardigrade Admin · Accepted Answer

(i) Use division method for finding HCF (ii) Check from the options.

Q. The HCF of two polynomials $A$ and $B$ using long division method was found to be $2 x + 1$ after two steps. The first two quotients obtained are $x$ and $(x + 1)$ . Find $A$ and $B$ . Given that degree of $A >$ degree of $B$ .

$A = 2 x^{3} + 3 x^{2} + x - 1, B = 2 x^{2} - 3 x + 1$

$A = 2 x^{3} - 3 x^{2} + x - 1, B = 2 x^{2} - 3 x - 1$

$A = 2 x^{3} + 3 x^{2} - 3 x - 1, B = 2 x^{2} - 3 x + 1$

$A = 2 x^{3} + 3 x^{2} + 3 x + 1, B = 2 x^{2} + 3 x + 1$

(i) Use division method for finding HCF
(ii) Check from the options.

Q. The HCF of two polynomials A and B using long division method was found to be 2x+1 after two steps. The first two quotients obtained are x and (x+1). Find A and B. Given that degree of A> degree of B.

A=2x3+3x2+x−1,B=2x2−3x+1

A=2x3−3x2+x−1,B=2x2−3x−1

A=2x3+3x2−3x−1,B=2x2−3x+1

A=2x3+3x2+3x+1,B=2x2+3x+1