The half-life of the reaction Xarrow Y, following first order kinetics, when the initial concentration of X is 0.01 mol L 1 and initial rate is 0.00352 mol L-1 min-1 will be

Question

The half-life of the reaction Xarrow Y, following first order kinetics, when the initial concentration of X is 0.01 mol L 1 and initial rate is 0.00352 mol L-1 min-1 will be (A) 19.69 min. (B) 1.969 min. (C) 7.75 min. (D) 17.75 min.

Tardigrade Admin · Accepted Answer

(dx/dt) =k[X] (For a first order reaction) 0.00352=k×0.01 ⇒ k=0.352 t1 /2 =(0.693/k) =(0.693/0.352) =1.969 min.

Q. The half-life of the reaction $X \to Y$ , following first order kinetics, when the initial concentration of $X$ is $0.01 m o l$ $L^{1}$ and initial rate is $0.00352 m o l L^{- 1}$ $mi n^{- 1}$ will be

$19.69 min$ .

$1.969 min$ .

$7.75 min$ .

$17.75 min$ .

$\frac{d x}{d t}$ $= k [X]$ (For a first order reaction)
$0.00352 = k \times 0.01$
$\Rightarrow k = 0.352$
$t_{1/2}$ $= \frac{0.693}{k}$ $= \frac{0.693}{0.352}$
$= 1.969 min$ .

Q. The half-life of the reaction X→Y, following first order kinetics, when the initial concentration of X is 0.01mol L1 and initial rate is 0.00352molL−1 min−1 will be

19.69min.

1.969min.

7.75min.

17.75min.