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Q. The half-life of the reaction $X\rightarrow Y$, following first order kinetics, when the initial concentration of $X$ is $0.01 \,mol$ $L ^{1}$ and initial rate is $0.00352\,mol L^{-1}$ $min^{-1}$ will be

Chemical Kinetics

Solution:

$\frac{dx}{dt}$ $=k\left[X\right]$ $\quad$ (For a first order reaction)
$0.00352=k\times0.01$
$\Rightarrow k=0.352$
$t_{1 /2}$ $=\frac{0.693}{k}$ $=\frac{0.693}{0.352}$
$=1.969 \,min$.