Question

The half-life of ${}_6{C}^{14}$ (if its $\lambda$ is $2.31\times 10^{-4})$ is

• A. $2\times 10^{2}yr$
• B. $3\times 10^{3}yr$
• C. $3.5\times 10^{4}yr$
• D. $4\times 10^{3}yr$

Answer 1

Answer: (B)

The half-life period is the time needed by a radioactive element to decay one half of its original weight.
It is expressed as half-life
$t_{1/2}=\frac{0.693}{\lambda }$
$=\frac{0.693}{2.31\times 10^{-4}}$
$=0.3\times 10^{4}yr$
$=3\times 10^{3}yr$