The haemoglobin from red blood corpuscles of most mammals contain approximately 0.33% of iron by mass. The molecular mass of haemoglobin is 67200. The number of iron atoms in each molecule of haemoglobin is

Question

The haemoglobin from red blood corpuscles of most mammals contain approximately 0.33% of iron by mass. The molecular mass of haemoglobin is 67200. The number of iron atoms in each molecule of haemoglobin is (A) 3 (B) 4 (C) 2 (D) 6

Tardigrade Admin · Accepted Answer

100 g haemoglobin has =0.33 g Fe 67200 g haemoglobin has Fe =(0.33/100)×67200=221.76 g 1 mole or NA molecules of haemoglobin has =(221.76/56) g atom of Fe = 3.96 g -atom of Fe =4.0 g atoms

Q. The haemoglobin from red blood corpuscles of most mammals contain approximately 0.33% of iron by mass. The molecular mass of haemoglobin is 67200. The number of iron atoms in each molecule of haemoglobin is

3

4

2

6

$100 g$ haemoglobin has $= 0.33 g F e$
$67200 g$ haemoglobin has $F e$
$= \frac{0.33}{100} \times 67200 = 221.76 g$ $1$ mole or $N_{A}$ molecules of haemoglobin has
$= \frac{221.76}{56} g$ atom of $F e$
$= 3.96 g$ -atom of $F e$
$= 4.0 g$ atoms

Q. The haemoglobin from red blood corpuscles of most mammals contain approximately 0.33% of iron by mass. The molecular mass of haemoglobin is 67200. The number of iron atoms in each molecule of haemoglobin is

3

4

2

6

100g haemoglobin has =0.33gFe 67200g haemoglobin has Fe =1000.33​×67200=221.76g 1 mole or NA​ molecules of haemoglobin has =56221.76​g atom of Fe =3.96g -atom of Fe =4.0g atoms

$100 g$ haemoglobin has $= 0.33 g F e$
$67200 g$ haemoglobin has $F e$
$= \frac{0.33}{100} \times 67200 = 221.76 g$ $1$ mole or $N_{A}$ molecules of haemoglobin has
$= \frac{221.76}{56} g$ atom of $F e$
$= 3.96 g$ -atom of $F e$
$= 4.0 g$ atoms