The H-H bond energy is 430 kJ mole -1 and Cl - Cl bond energy is 240 k J mole -1, Δ H for H C l is -90 k J. The H-C l bond energy is about:

Question

The H-H bond energy is 430 kJ mole -1 and Cl - Cl bond energy is 240 k J mole -1, Δ H for H C l is -90 k J. The H-C l bond energy is about: (A) 180 k J mole -1 (B) 360 k J mole -1 (C) 213 k J mole -1 (D) 425 k J mole -1

Tardigrade Admin · Accepted Answer

(1/2) H2+(1/2) C l2 arrow H C l ; Δ H=-90 k J -Δ H=(1/2) B ⋅ E ⋅(H-H)+(1/2) B ⋅ E(C l-C l) or -90=(1/2)[430]+(1/2)[240]-B ⋅ E ⋅(H-C l) or -90=215+120-B ⋅ E ⋅(H-C l) B. E ⋅(H-C l)=215+120+90 =425 k J mole -1

Q. The $H - H$ bond energy is $430 k J$ mole $^{- 1}$ and $Cl - Cl$ bond energy is $240 k J$ mole $^{- 1}, Δ H$ for $H Cl$ is $- 90 k J$ . The $H - Cl$ bond energy is about:

$180 k J$ mole $^{- 1}$

$360 k J$ mole $^{- 1}$

$213 k J$ mole $^{- 1}$

$425 k J$ mole $^{- 1}$

Q. The H−H bond energy is 430kJ mole −1 and Cl−Cl bond energy is 240kJ mole −1,ΔH for HCl is −90kJ. The H−Cl bond energy is about:

180kJ mole −1

360kJ mole −1

213kJ mole −1

425kJ mole −1

21​H2​+21​Cl2​→HCl; ΔH=−90kJ −ΔH=21​B⋅E⋅(H−H)+21​B⋅E(Cl−Cl) or −90=21​[430]+21​[240]−B⋅E⋅(H−Cl) or −90=215+120−B⋅E⋅(H−Cl) B. E⋅(H−Cl)=215+120+90 =425kJ mole −1

Q. The $H - H$ bond energy is $430 k J$ mole $^{- 1}$ and $Cl - Cl$ bond energy is $240 k J$ mole $^{- 1}, Δ H$ for $H Cl$ is $- 90 k J$ . The $H - Cl$ bond energy is about:

$180 k J$ mole $^{- 1}$

$360 k J$ mole $^{- 1}$

$213 k J$ mole $^{- 1}$

$425 k J$ mole $^{- 1}$